In the reaction,the product [X] will be: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction between two molecules of cyclohexanone in the presence of a base (dilute $NaOH$) and heat $(\Delta)$ is an aldol condensation reactio

Vedclass · Accepted Answer

Vedclass · Answer

(D) The reaction between two molecules of cyclohexanone in the presence of a base (dilute $NaOH$) and heat $(\Delta)$ is an aldol condensation reaction.$1$. First,the base abstracts an $\alpha$-hydrogen from one molecule of cyclohexanone to form an enolate ion.$2$. The enolate ion attacks the carbonyl carbon of another cyclohexanone molecule to form a $\beta$-hydroxy ketone (aldol).$3$. Upon heating $(\Delta)$,the $\beta$-hydroxy ketone undergoes dehydration (loss of $H_2O$) to form an $\alpha,\beta$-unsaturated ketone as the final product $[X]$.

In the reaction,the product $[X]$ will be:

Similar Questions

The reagent$(s)$ which can be used to distinguish acetophenone from benzophenone is (are):

The solution of Fehling $B$ contains . . . . . . .

Identify the set in which $X$ and $Y$ are correctly matched for the reaction of benzaldehyde with a reagent $X$ to form product $Y$.

$A$ reaction of benzonitrile with one equivalent of $CH_{3}MgBr$ followed by hydrolysis produces a yellow liquid $P$. The compound $P$ will give a positive result for which of the following tests?

Which of the following will not give the iodoform test?

Vedclass Test Series

Exam Paper Generator

Online Exam Module